[4] | 1 | /* |
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| 2 | * This program is free software; you can redistribute it and/or modify |
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| 3 | * it under the terms of the GNU General Public License as published by |
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| 4 | * the Free Software Foundation; either version 2 of the License, or |
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| 5 | * (at your option) any later version. |
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| 6 | * |
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| 7 | * This program is distributed in the hope that it will be useful, |
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| 8 | * but WITHOUT ANY WARRANTY; without even the implied warranty of |
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| 9 | * MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the |
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| 10 | * GNU General Public License for more details. |
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| 11 | * |
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| 12 | * You should have received a copy of the GNU General Public License |
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| 13 | * along with this program; if not, write to the Free Software |
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| 14 | * Foundation, Inc., 675 Mass Ave, Cambridge, MA 02139, USA. |
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| 15 | */ |
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| 16 | |
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| 17 | /* |
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| 18 | * PlaceNode2.java |
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| 19 | * Copyright (C) 1999 University of Waikato, Hamilton, New Zealand |
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| 20 | * |
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| 21 | */ |
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| 22 | |
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| 23 | package weka.gui.treevisualizer; |
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| 24 | |
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| 25 | import java.util.*; |
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| 26 | |
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| 27 | /** |
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| 28 | * This class will place the Nodes of a tree. <p> |
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| 29 | * |
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| 30 | * It will place these nodes so that they fall at evenly below their parent. |
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| 31 | * It will then go through and look for places where nodes fall on the wrong |
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| 32 | * side of other nodes |
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| 33 | * when it finds one it will trace back up the tree to find the first common |
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| 34 | * sibling group these two nodes have |
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| 35 | * And it will adjust the spacing between these two siblings so that the two |
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| 36 | * nodes no longer overlap. |
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| 37 | * This is nasty to calculate with , and takes a while with the current |
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| 38 | * algorithm I am using to do this.<p> |
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| 39 | * |
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| 40 | * |
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| 41 | * @author Malcolm Ware (mfw4@cs.waikato.ac.nz) |
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| 42 | * @version $Revision: 1.4 $ |
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| 43 | */ |
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| 44 | public class PlaceNode2 implements NodePlace { |
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| 45 | /** The space each row will take up. */ |
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| 46 | private double m_yRatio; |
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| 47 | |
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| 48 | /** An array that lists the groups and information about them. */ |
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| 49 | private Group[] m_groups; |
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| 50 | |
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| 51 | /** An array that lists the levels and information about them. */ |
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| 52 | private Level[] m_levels; |
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| 53 | |
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| 54 | /** The Number of groups the tree has */ |
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| 55 | private int m_groupNum; |
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| 56 | |
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| 57 | /** The number of levels the group tree has */ |
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| 58 | private int m_levelNum; |
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| 59 | |
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| 60 | /** |
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| 61 | * The Funtion to call to have the nodes arranged. |
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| 62 | * |
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| 63 | * @param r The top node of the tree to arrange. |
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| 64 | */ |
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| 65 | public void place(Node r) { |
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| 66 | //note i might write count groups into the node class as well as |
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| 67 | //it may be useful too; |
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| 68 | |
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| 69 | m_groupNum = Node.getGCount(r,0); //i could swap over to the node class |
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| 70 | //group count,but this works os i'm not gonna |
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| 71 | m_groups = new Group[m_groupNum]; |
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| 72 | |
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| 73 | for (int noa = 0;noa < m_groupNum;noa++) { |
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| 74 | m_groups[noa] = new Group(); |
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| 75 | m_groups[noa].m_gap = 3; |
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| 76 | m_groups[noa].m_start = -1; |
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| 77 | } |
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| 78 | |
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| 79 | groupBuild(r); |
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| 80 | m_levelNum = Node.getHeight(r,0); |
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| 81 | m_yRatio = 1 / (double)(m_levelNum + 1); |
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| 82 | |
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| 83 | m_levels = new Level[m_levelNum]; |
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| 84 | |
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| 85 | for (int noa = 0;noa < m_levelNum;noa++) { |
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| 86 | m_levels[noa] = new Level(); |
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| 87 | } |
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| 88 | r.setTop(m_yRatio); |
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| 89 | yPlacer(); |
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| 90 | r.setCenter(0); |
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| 91 | xPlacer(0); |
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| 92 | |
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| 93 | |
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| 94 | //ok now i just have to untangle then scale down |
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| 95 | //note instead of starting with coords between 1 and 0 i will |
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| 96 | //use ints then scale them down |
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| 97 | //i will scale them down either by all relative to the largest |
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| 98 | //line or by each line individually |
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| 99 | |
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| 100 | untangle2(); |
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| 101 | |
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| 102 | scaleByMax(); |
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| 103 | //scaleByInd(); |
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| 104 | } |
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| 105 | |
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| 106 | |
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| 107 | /* |
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| 108 | private void thinner() |
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| 109 | { |
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| 110 | //what this function does is it retains the symmetry of the |
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| 111 | // parent node about the children but the children are no longer evenly |
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| 112 | //spaced this stops children from being pushed too far to the sides |
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| 113 | //,note this algorithm may need the method altered as it may |
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| 114 | // require heavy optimisation to go at any decent speed |
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| 115 | |
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| 116 | Node r,s; |
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| 117 | Edge e; |
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| 118 | double parent_x; |
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| 119 | for (int noa = group_num - 1;noa >= 0;noa--) |
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| 120 | { |
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| 121 | Vector shifts = new Vector(20,10); |
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| 122 | shifts.addElement(0); |
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| 123 | int g_num = 0;//this is the offset from groups.m_start to get the right 1 |
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| 124 | r = groups[noa].m_p; |
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| 125 | parent_x = r.getCenter(); |
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| 126 | for (int nob = 1;(e = r.getChild(nob)) != null;nob++) |
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| 127 | { |
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| 128 | double margin; |
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| 129 | s = e.getTarget(); |
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| 130 | margin = s_getCenter - r.getChild(nob - 1).getTarget().getCenter-1 |
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| 131 | - shift.elementAt(nob-1); |
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| 132 | if (margin > 0) |
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| 133 | { |
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| 134 | margin = check_down(s,g_num,margin); |
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| 135 | if (margin > 0) |
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| 136 | { |
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| 137 | shift.addElement(-margin); |
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| 138 | } |
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| 139 | else |
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| 140 | { |
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| 141 | shift.addElement(0); |
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| 142 | } |
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| 143 | } |
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| 144 | else |
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| 145 | { |
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| 146 | shift.addElement(0); |
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| 147 | } |
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| 148 | if (s.getChild(0) != null) |
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| 149 | { |
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| 150 | g_num++; |
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| 151 | } |
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| 152 | } |
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| 153 | } |
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| 154 | } |
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| 155 | |
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| 156 | |
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| 157 | private double check_down(Node r,int gn,double m) |
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| 158 | { |
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| 159 | //note i need to know where the children of the |
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| 160 | //other changers are to properly overlap check |
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| 161 | //to do this i think the best way is to go up the other group |
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| 162 | //parents line and see if it goes through the current group |
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| 163 | //this means to save time i need to know the level that is being |
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| 164 | //worked with along with the group |
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| 165 | |
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| 166 | Edge e; |
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| 167 | for (int noa = 0;(e = r.getChild(noa)) != null;noa++) |
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| 168 | { |
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| 169 | |
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| 170 | } |
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| 171 | } |
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| 172 | */ |
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| 173 | |
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| 174 | |
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| 175 | /** |
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| 176 | * This will set initial places for the x coord of the nodes. |
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| 177 | * @param start The `number for the first group to start on (I think). |
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| 178 | */ |
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| 179 | private void xPlacer(int start) { |
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| 180 | //this can be one of a few x_placers (the first) |
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| 181 | //it will work by placing 1 space inbetween each node |
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| 182 | //ie the first at 0 the second at 1 and so on |
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| 183 | //then it will add to this value the place of the parent |
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| 184 | //node - half of the size |
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| 185 | //i will break this up into several functions |
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| 186 | //first the gap setter; |
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| 187 | //then the shifter |
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| 188 | //it will require a vector shift function added to the node class |
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| 189 | //i will write an additional shifter for the untangler |
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| 190 | //for its particular situation |
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| 191 | |
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| 192 | Node r; |
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| 193 | Edge e; |
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| 194 | if (m_groupNum > 0) { |
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| 195 | m_groups[0].m_p.setCenter(0); |
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| 196 | for (int noa = start;noa < m_groupNum;noa++) { |
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| 197 | int nob,alter =0; |
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| 198 | double c = m_groups[noa].m_gap; |
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| 199 | r = m_groups[noa].m_p; |
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| 200 | for (nob = 0;(e = r.getChild(nob)) != null;nob++) { |
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| 201 | if (e.getTarget().getParent(0) == e) { |
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| 202 | e.getTarget().setCenter(nob * c); |
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| 203 | } |
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| 204 | else { |
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| 205 | alter++; |
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| 206 | } |
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| 207 | } |
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| 208 | m_groups[noa].m_size = (nob - 1 - alter) * c; |
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| 209 | xShift(noa); |
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| 210 | } |
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| 211 | } |
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| 212 | } |
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| 213 | |
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| 214 | /** |
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| 215 | * This will shift a group of nodes to be aligned under their parent. |
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| 216 | * @param n The group number to shift |
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| 217 | */ |
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| 218 | private void xShift(int n) { |
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| 219 | Edge e; |
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| 220 | Node r = m_groups[n].m_p; |
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| 221 | double h = m_groups[n].m_size / 2; |
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| 222 | double c = m_groups[n].m_p.getCenter(); |
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| 223 | double m = c - h; |
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| 224 | m_groups[n].m_left = m; |
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| 225 | m_groups[n].m_right = c + h; |
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| 226 | |
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| 227 | for (int noa = 0;(e = r.getChild(noa)) != null;noa++) { |
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| 228 | if (e.getTarget().getParent(0) == e) { |
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| 229 | e.getTarget().adjustCenter(m); |
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| 230 | } |
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| 231 | } |
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| 232 | } |
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| 233 | |
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| 234 | /** |
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| 235 | * This scales all the x values to be between 0 and 1. |
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| 236 | */ |
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| 237 | private void scaleByMax() { |
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| 238 | //ammendment to what i may have commented before |
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| 239 | //this takes the lowest x and highest x and uses that as the scaling |
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| 240 | //factor |
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| 241 | double l_x = 5000,h_x = -5000; |
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| 242 | for (int noa = 0;noa < m_groupNum;noa++) { |
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| 243 | if (l_x > m_groups[noa].m_left) { |
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| 244 | l_x = m_groups[noa].m_left; |
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| 245 | } |
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| 246 | |
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| 247 | if (h_x < m_groups[noa].m_right) { |
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| 248 | h_x = m_groups[noa].m_right; |
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| 249 | } |
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| 250 | } |
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| 251 | |
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| 252 | Edge e; |
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| 253 | Node r,s; |
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| 254 | double m_scale = h_x - l_x + 1; |
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| 255 | if (m_groupNum > 0) { |
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| 256 | r = m_groups[0].m_p; |
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| 257 | r.setCenter((r.getCenter() - l_x) / m_scale); |
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| 258 | //System.out.println("from scaler " + l_x + " " + m_scale); |
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| 259 | for (int noa = 0; noa < m_groupNum;noa++) { |
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| 260 | r = m_groups[noa].m_p; |
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| 261 | for (int nob = 0;(e = r.getChild(nob)) != null;nob++) { |
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| 262 | s = e.getTarget(); |
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| 263 | if (s.getParent(0) == e) { |
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| 264 | s.setCenter((s.getCenter() - l_x) / m_scale); |
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| 265 | } |
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| 266 | } |
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| 267 | } |
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| 268 | } |
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| 269 | } |
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| 270 | |
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| 271 | /** |
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| 272 | * This scales the x values to between 0 and 1 for each individual line |
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| 273 | * rather than doing them all at once. |
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| 274 | */ |
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| 275 | private void scaleByInd() { |
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| 276 | //ammendment to what i may have commented before |
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| 277 | //this takes the lowest x and highest x on each line and uses that for |
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| 278 | //the line in question |
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| 279 | double l_x,h_x; |
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| 280 | |
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| 281 | Edge e; |
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| 282 | Node r,s; |
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| 283 | r = m_groups[0].m_p; |
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| 284 | r.setCenter(.5); |
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| 285 | double m_scale; |
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| 286 | for (int noa = 0;noa < m_levelNum;noa++) { |
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| 287 | l_x = m_groups[m_levels[noa].m_start].m_left; |
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| 288 | h_x = m_groups[m_levels[noa].m_end].m_right; |
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| 289 | m_scale = h_x - l_x + 1; |
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| 290 | for (int nob = m_levels[noa].m_start; nob <= m_levels[noa].m_end;nob++) { |
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| 291 | r = m_groups[nob].m_p; |
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| 292 | for (int noc = 0;(e = r.getChild(noc)) != null;noc++) { |
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| 293 | s = e.getTarget(); |
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| 294 | if (s.getParent(0) == e) { |
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| 295 | s.setCenter((s.getCenter() - l_x) / m_scale); |
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| 296 | } |
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| 297 | } |
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| 298 | } |
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| 299 | } |
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| 300 | } |
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| 301 | |
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| 302 | /** |
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| 303 | * This untangles the nodes so that they will will fall on the correct |
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| 304 | * side of the other nodes along their row. |
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| 305 | */ |
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| 306 | private void untangle2() { |
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| 307 | Ease a; |
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| 308 | Edge e; |
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| 309 | Node r,nf = null,ns = null,mark; |
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| 310 | int l = 0,times = 0; |
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| 311 | int f,s,tf = 0,ts = 0,pf,ps; |
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| 312 | while ((a = overlap(l)) != null) { |
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| 313 | times++; |
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| 314 | //System.out.println("from untang 2 " + group_num); |
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| 315 | f = a.m_place; |
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| 316 | s = a.m_place + 1; |
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| 317 | while (f != s) { |
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| 318 | a.m_lev--; |
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| 319 | tf = f; |
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| 320 | ts = s; |
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| 321 | f = m_groups[f].m_pg; |
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| 322 | s = m_groups[s].m_pg; |
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| 323 | } |
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| 324 | l = a.m_lev; |
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| 325 | pf = 0; |
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| 326 | ps = 0; |
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| 327 | r = m_groups[f].m_p; |
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| 328 | mark = m_groups[tf].m_p; |
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| 329 | nf = null; |
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| 330 | ns = null; |
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| 331 | for (int noa = 0; nf != mark;noa++) { |
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| 332 | pf++; |
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| 333 | nf = r.getChild(noa).getTarget(); |
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| 334 | } |
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| 335 | mark = m_groups[ts].m_p; |
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| 336 | for (int noa = pf; ns != mark;noa++) { |
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| 337 | ps++; //the number of gaps between the two nodes |
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| 338 | ns = r.getChild(noa).getTarget(); |
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| 339 | } |
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| 340 | //m_groups[f].gap = |
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| 341 | // Math.ceil((a.amount / (double)ps) + m_groups[f].gap); |
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| 342 | //note for this method i do not need the group gap ,but i will leave |
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| 343 | //it for the other methods; |
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| 344 | Vector o_pos = new Vector(20,10); |
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| 345 | for (int noa = 0;(e = r.getChild(noa)) != null;noa++) { |
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| 346 | if (e.getTarget().getParent(0) == e) { |
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| 347 | Double tem = new Double(e.getTarget().getCenter()); |
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| 348 | o_pos.addElement(tem); |
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| 349 | } |
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| 350 | } |
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| 351 | |
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| 352 | pf--; |
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| 353 | double inc = a.m_amount / (double)ps; |
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| 354 | for (int noa = 0;(e = r.getChild(noa)) != null;noa++) { |
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| 355 | ns = e.getTarget(); |
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| 356 | if (ns.getParent(0) == e) { |
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| 357 | if (noa > pf + ps) { |
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| 358 | ns.adjustCenter(a.m_amount); |
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| 359 | } |
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| 360 | else if (noa > pf) { |
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| 361 | ns.adjustCenter(inc * (double)(noa - pf)); |
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| 362 | } |
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| 363 | } |
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| 364 | } |
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| 365 | |
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| 366 | nf = r.getChild(0).getTarget(); |
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| 367 | inc = ns.getCenter() - nf.getCenter(); |
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| 368 | m_groups[f].m_size = inc; |
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| 369 | m_groups[f].m_left = r.getCenter() - inc / 2; |
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| 370 | m_groups[f].m_right = m_groups[f].m_left + inc; |
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| 371 | inc = m_groups[f].m_left - nf.getCenter(); |
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| 372 | |
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| 373 | double shift; |
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| 374 | int g_num = 0; |
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| 375 | for (int noa = 0;(e = r.getChild(noa)) != null;noa++) { |
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| 376 | ns = e.getTarget(); |
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| 377 | if (ns.getParent(0) == e) { |
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| 378 | ns.adjustCenter(inc); |
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| 379 | shift = ns.getCenter() - |
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| 380 | ((Double)o_pos.elementAt(noa)).doubleValue(); |
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| 381 | if (ns.getChild(0) != null) { |
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| 382 | moveSubtree(m_groups[f].m_start + g_num,shift); |
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| 383 | g_num++; |
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| 384 | } |
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| 385 | } |
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| 386 | //ns.adjustCenter(-shift); |
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| 387 | } |
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| 388 | //zero_offset(r); |
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| 389 | |
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| 390 | //x_placer(f); |
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| 391 | } |
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| 392 | } |
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| 393 | |
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| 394 | |
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| 395 | /** |
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| 396 | * This will recursively shift a sub there to be centered about |
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| 397 | * a particular value. |
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| 398 | * @param n The first group in the sub tree. |
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| 399 | * @param o The point to start shifting the subtree. |
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| 400 | */ |
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| 401 | private void moveSubtree(int n,double o) { |
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| 402 | Edge e; |
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| 403 | Node r = m_groups[n].m_p; |
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| 404 | for (int noa = 0;(e = r.getChild(noa)) != null;noa++) { |
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| 405 | if (e.getTarget().getParent(0) == e) { |
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| 406 | e.getTarget().adjustCenter(o); |
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| 407 | } |
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| 408 | } |
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| 409 | m_groups[n].m_left += o; |
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| 410 | m_groups[n].m_right += o; |
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| 411 | if (m_groups[n].m_start != -1) { |
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| 412 | for (int noa = m_groups[n].m_start;noa <= m_groups[n].m_end;noa++) { |
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| 413 | moveSubtree(noa,o); |
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| 414 | } |
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| 415 | } |
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| 416 | } |
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| 417 | |
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| 418 | |
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| 419 | /** |
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| 420 | * This will untangle the nodes in the tree so that they fall on the |
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| 421 | * correct side of each other. |
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| 422 | */ |
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| 423 | private void untangle() { |
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| 424 | Ease a; |
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| 425 | Edge e; |
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| 426 | Node r,nf = null,ns = null,mark; |
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| 427 | int l = 0,times = 0; |
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| 428 | int f,s,tf = 0,ts = 0,pf,ps; |
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| 429 | while ((a = overlap(l)) != null) { |
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| 430 | times++; |
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| 431 | //System.out.println(group_num); |
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| 432 | f = a.m_place; |
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| 433 | s = a.m_place + 1; |
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| 434 | while (f != s) { |
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| 435 | a.m_lev--; |
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| 436 | tf = f; |
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| 437 | ts = s; |
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| 438 | f = m_groups[f].m_pg; |
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| 439 | s = m_groups[s].m_pg; |
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| 440 | } |
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| 441 | l = a.m_lev; |
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| 442 | pf = 0; |
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| 443 | ps = 0; |
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| 444 | r = m_groups[f].m_p; |
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| 445 | mark = m_groups[tf].m_p; |
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| 446 | nf = null; |
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| 447 | ns = null; |
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| 448 | for (int noa = 0; nf != mark;noa++) { |
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| 449 | pf++; |
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| 450 | nf = r.getChild(noa).getTarget(); |
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| 451 | } |
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| 452 | mark = m_groups[ts].m_p; |
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| 453 | for (int noa = pf; ns != mark;noa++) { |
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| 454 | ps++; //the number of gaps between the two nodes |
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| 455 | ns = r.getChild(noa).getTarget(); |
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| 456 | } |
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| 457 | m_groups[f].m_gap = |
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| 458 | Math.ceil((a.m_amount / (double)ps) + m_groups[f].m_gap); |
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| 459 | |
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| 460 | xPlacer(f); |
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| 461 | } |
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| 462 | } |
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| 463 | |
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| 464 | /** |
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| 465 | * This will find an overlap and then return information about that overlap |
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| 466 | * @param l The level to start on. |
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| 467 | * @return null if there was no overlap , otherwise an object containing |
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| 468 | * the group number that overlaps (only need one) how much they overlap by, |
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| 469 | * and the level they overlap on. |
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| 470 | */ |
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| 471 | private Ease overlap(int l) { |
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| 472 | Ease a = new Ease(); |
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| 473 | for (int noa = l;noa < m_levelNum;noa++) { |
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| 474 | for (int nob = m_levels[noa].m_start;nob < m_levels[noa].m_end;nob++) { |
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| 475 | a.m_amount = m_groups[nob].m_right - m_groups[nob+1].m_left + 2; |
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| 476 | //System.out.println(m_groups[nob].m_right + " + " + |
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| 477 | // m_groups[nob+1].m_left + " = " + a.amount); |
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| 478 | if (a.m_amount >= 0) { |
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| 479 | a.m_amount++; |
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| 480 | a.m_lev = noa; |
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| 481 | a.m_place = nob; |
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| 482 | return a; |
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| 483 | } |
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| 484 | } |
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| 485 | } |
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| 486 | return null; |
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| 487 | } |
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| 488 | |
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| 489 | /* private int count_m_groups(Node r,int l) |
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| 490 | { |
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| 491 | Edge e; |
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| 492 | if (r.getChild(0) != null) |
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| 493 | { |
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| 494 | l++; |
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| 495 | } |
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| 496 | for (int noa = 0;(e = r.getChild(noa)) != null;noa++) |
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| 497 | { |
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| 498 | l = count_groups(e.getTarget(),l); |
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| 499 | } |
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| 500 | |
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| 501 | return l; |
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| 502 | } |
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| 503 | */ |
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| 504 | |
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| 505 | /** |
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| 506 | * This function sets up the height of each node, and also fills the |
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| 507 | * levels array with information about what the start and end groups on that |
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| 508 | * level are. |
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| 509 | */ |
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| 510 | private void yPlacer() { |
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| 511 | //note this places the y height and sets up the levels array |
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| 512 | double changer = m_yRatio; |
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| 513 | int lev_place = 0; |
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| 514 | if (m_groupNum > 0) { |
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| 515 | m_groups[0].m_p.setTop(m_yRatio); |
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| 516 | m_levels[0].m_start = 0; |
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| 517 | |
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| 518 | for (int noa = 0;noa < m_groupNum;noa++) { |
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| 519 | if (m_groups[noa].m_p.getTop() != changer) { |
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| 520 | m_levels[lev_place].m_end = noa - 1; |
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| 521 | lev_place++; |
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| 522 | m_levels[lev_place].m_start = noa; |
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| 523 | changer = m_groups[noa].m_p.getTop(); |
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| 524 | } |
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| 525 | nodeY(m_groups[noa].m_p); |
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| 526 | } |
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| 527 | m_levels[lev_place].m_end = m_groupNum - 1; |
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| 528 | } |
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| 529 | } |
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| 530 | |
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| 531 | /** |
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| 532 | * This will set all of the children node of a particular node to their |
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| 533 | * height. |
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| 534 | * @param r The parent node of the children to set their height. |
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| 535 | */ |
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| 536 | private void nodeY(Node r) { |
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| 537 | Edge e; |
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| 538 | double h = r.getTop() + m_yRatio; |
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| 539 | for (int noa = 0;(e = r.getChild(noa)) != null;noa++) { |
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| 540 | if (e.getTarget().getParent(0) == e) { |
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| 541 | e.getTarget().setTop(h); |
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| 542 | if (!e.getTarget().getVisible()) { |
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| 543 | //System.out.println("oh bugger"); |
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| 544 | } |
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| 545 | } |
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| 546 | } |
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| 547 | } |
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| 548 | |
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| 549 | /** |
---|
| 550 | * This starts to create the information about the sibling groups. |
---|
| 551 | * As more groups are created the for loop in this will check those groups |
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| 552 | * for lower groups. |
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| 553 | * @param r The top node. |
---|
| 554 | */ |
---|
| 555 | private void groupBuild(Node r) { |
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| 556 | if (m_groupNum > 0) { |
---|
| 557 | m_groupNum = 0; |
---|
| 558 | m_groups[0].m_p = r; |
---|
| 559 | m_groupNum++; |
---|
| 560 | //note i need to count up the num of groups first |
---|
| 561 | //woe is me |
---|
| 562 | for (int noa = 0;noa < m_groupNum ;noa++) { |
---|
| 563 | groupFind(m_groups[noa].m_p,noa); |
---|
| 564 | } |
---|
| 565 | } |
---|
| 566 | } |
---|
| 567 | |
---|
| 568 | /** |
---|
| 569 | * This is called to build the rest of the grouping information. |
---|
| 570 | * @param r The parent of the group. |
---|
| 571 | * @param pg The number for the parents group. |
---|
| 572 | */ |
---|
| 573 | private void groupFind(Node r,int pg) { |
---|
| 574 | Edge e; |
---|
| 575 | boolean first = true; |
---|
| 576 | for (int noa = 0;(e = r.getChild(noa)) != null;noa++) { |
---|
| 577 | if (e.getTarget().getParent(0) == e) { |
---|
| 578 | if (e.getTarget().getChild(0) != null && e.getTarget().getCVisible()) { |
---|
| 579 | if (first) { |
---|
| 580 | m_groups[pg].m_start = m_groupNum; |
---|
| 581 | first = false; |
---|
| 582 | } |
---|
| 583 | m_groups[pg].m_end = m_groupNum; |
---|
| 584 | m_groups[m_groupNum].m_p = e.getTarget(); |
---|
| 585 | m_groups[m_groupNum].m_pg = pg; |
---|
| 586 | m_groups[m_groupNum].m_id = m_groupNum; //just in case I ever need |
---|
| 587 | //this info |
---|
| 588 | m_groupNum++; |
---|
| 589 | } |
---|
| 590 | } |
---|
| 591 | } |
---|
| 592 | } |
---|
| 593 | |
---|
| 594 | |
---|
| 595 | //note these three classes are only to help organise the data and are |
---|
| 596 | //inter related between each other and this placer class |
---|
| 597 | //so don't mess with them or try to use them somewhere else |
---|
| 598 | //(because that would be a mistake and I would pity you) |
---|
| 599 | |
---|
| 600 | |
---|
| 601 | /** |
---|
| 602 | * Inner class for containing the level data. |
---|
| 603 | */ |
---|
| 604 | private class Level { |
---|
| 605 | /** The number for the group on the left of this level. */ |
---|
| 606 | public int m_start; |
---|
| 607 | /** The number for the group on the right of this level. */ |
---|
| 608 | public int m_end; |
---|
| 609 | |
---|
| 610 | /** These two params would appear to not be used. */ |
---|
| 611 | public int m_left; |
---|
| 612 | public int m_right; |
---|
| 613 | } |
---|
| 614 | |
---|
| 615 | /** |
---|
| 616 | * Inner class for containing the grouping data. |
---|
| 617 | */ |
---|
| 618 | private class Group { |
---|
| 619 | /** The parent node of this group. */ |
---|
| 620 | public Node m_p; |
---|
| 621 | |
---|
| 622 | /** The group number for the parent of this group. */ |
---|
| 623 | public int m_pg; |
---|
| 624 | |
---|
| 625 | /** The gap size for the distance between the nodes in this group. */ |
---|
| 626 | public double m_gap; |
---|
| 627 | |
---|
| 628 | /** The leftmost position of this group. */ |
---|
| 629 | public double m_left; |
---|
| 630 | |
---|
| 631 | /** The rightmost position of this group. */ |
---|
| 632 | public double m_right; |
---|
| 633 | |
---|
| 634 | /** The size of this group. */ |
---|
| 635 | public double m_size; |
---|
| 636 | |
---|
| 637 | /** The start node of this group. */ |
---|
| 638 | public int m_start; |
---|
| 639 | |
---|
| 640 | /** The end node of this group. */ |
---|
| 641 | public int m_end; |
---|
| 642 | |
---|
| 643 | /** The group number for this group. (may not be used!?). */ |
---|
| 644 | public int m_id; |
---|
| 645 | } |
---|
| 646 | |
---|
| 647 | /** |
---|
| 648 | * An inner class used to report information about any tangles found. |
---|
| 649 | */ |
---|
| 650 | private class Ease { |
---|
| 651 | /** The number of the group on the left of the tangle. */ |
---|
| 652 | public int m_place; |
---|
| 653 | /** The distance they were tangled. */ |
---|
| 654 | public double m_amount; |
---|
| 655 | /** The level on which they were tangled. */ |
---|
| 656 | public int m_lev; |
---|
| 657 | } |
---|
| 658 | } |
---|
| 659 | |
---|
| 660 | |
---|
| 661 | |
---|
| 662 | |
---|
| 663 | |
---|
| 664 | |
---|
| 665 | |
---|
| 666 | |
---|
| 667 | |
---|
| 668 | |
---|
| 669 | |
---|
| 670 | |
---|
| 671 | |
---|
| 672 | |
---|